Showing posts with label data structures. Show all posts
Showing posts with label data structures. Show all posts

Sunday, January 13, 2019

Modify an Object Nested Within an Object

Basic Data Structures: Modify an Object Nested Within an Object
Now let's take a look at a slightly more complex object. Object properties can be nested to an arbitrary depth, and their values can be any type of data supported by JavaScript, including arrays and even other objects. Consider the following:

let nestedObject = {
  id: 28802695164,
  date: 'December 31, 2016',
  data: {
    totalUsers: 99,
    online: 80,
    onlineStatus: {
      active: 67,
      away: 13
    }
  }
};
nestedObject has three unique keys: id, whose value is a number, date whose value is a string, and data, whose value is an object which has yet another object nested within it. While structures can quickly become complex, we can still use the same notations to access the information we need.


Here we've defined an object, userActivity, which includes another object nested within it. You can modify properties on this nested object in the same way you modified properties in the last challenge. Set the value of the online key to 45.

Friday, January 11, 2019

Basic Data Structures: Add Key-Value Pairs to JavaScript Objects

Basic Data Structures: Add Key-Value Pairs to JavaScript Objects
At their most basic, objects are just collections of key-value pairs, or in other words, pieces of data mapped to unique identifiers that we call properties or keys. Let's take a look at a very simple example:

let FCC_User = {
  username: 'awesome_coder',
  followers: 572,
  points: 1741,
  completedProjects: 15
};
The above code defines an object called FCC_User that has four properties, each of which map to a specific value. If we wanted to know the number of followers FCC_User has, we can access that property by writing:

let userData = FCC_User.followers;
// userData equals 572
This is called dot notation. Alternatively, we can also access the property with brackets, like so:

let userData = FCC_User['followers']
// userData equals 572
Notice that with bracket notation, we enclosed followers in quotes. This is because the brackets actually allow us to pass a variable in to be evaluated as a property name (hint: keep this in mind for later!). Had we passed followers in without the quotes, the JavaScript engine would have attempted to evaluate it as a variable, and a ReferenceError: followers is not defined would have been thrown.


Using the same syntax, we can also add new key-value pairs to objects. We've created a foods object with three entries. Add three more entries: bananas with a value of 13, grapes with a value of 35, and strawberries with a value of 27.

Saturday, January 5, 2019

Basic Data Structures: Iterate Through All an Array's Items Using For Loops

Basic Data Structures: Iterate Through All an Array's Items Using For Loops
Sometimes when working with arrays, it is very handy to be able to iterate through each item to find one or more elements that we might need, or to manipulate an array based on which data items meet a certain set of criteria. JavaScript offers several built in methods that each iterate over arrays in slightly different ways to achieve different results (such as every(), forEach(), map(), etc.), however the technique which is most flexible and offers us the greatest amount of control is a simple for loop.

Consider the following:

function greaterThanTen(arr) {
  let newArr = [];
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] > 10) {
      newArr.push(arr[i]);
    }
  }
  return newArr;
}

greaterThanTen([2, 12, 8, 14, 80, 0, 1]);
// returns [12, 14, 80]
Using a for loop, this function iterates through and accesses each element of the array, and subjects it to a simple test that we have created. In this way, we have easily and programmatically determined which data items are greater than 10, and returned a new array containing those items.


We have defined a function, filteredArray, which takes arr, a nested array, and elem as arguments, and returns a new array. elem represents an element that may or may not be present on one or more of the arrays nested within arr. Modify the function, using a for loop, to return a filtered version of the passed array such that any array nested within arr containing elem has been removed.

Monday, December 31, 2018

Basic Data Structures: Check For The Presence of an Element With indexOf()

Days: 45-47

Since arrays can be changed, or mutated, at any time, there's no guarantee about where a particular piece of data will be on a given array, or if that element even still exists. Luckily, JavaScript provides us with another built-in method, indexOf(), that allows us to quickly and easily check for the presence of an element on an array. indexOf() takes an element as a parameter, and when called, it returns the position, or index, of that element, or -1 if the element does not exist on the array.

For example:

let fruits = ['apples', 'pears', 'oranges', 'peaches', 'pears'];

fruits.indexOf('dates') // returns -1
fruits.indexOf('oranges') // returns 2
fruits.indexOf('pears') // returns 1, the first index at which the element exists

indexOf() can be incredibly useful for quickly checking for the presence of an element on an array. We have defined a function, quickCheck, that takes an array and an element as arguments. Modify the function using indexOf() so that it returns true if the passed element exists on the array, and false if it does not.

Friday, December 28, 2018

Combine Arrays with the Spread Operator


Another huge advantage of the spread operator, is the ability to combine arrays, or to insert all the elements of one array into another, at any index. With more traditional syntaxes, we can concatenate arrays, but this only allows us to combine arrays at the end of one, and at the start of another. Spread syntax makes the following operation extremely simple:

let thisArray = ['sage', 'rosemary', 'parsley', 'thyme'];

let thatArray = ['basil', 'cilantro', ...thisArray, 'coriander'];
// thatArray now equals ['basil', 'cilantro', 'sage', 'rosemary', 'parsley', 'thyme', 'coriander']
Using spread syntax, we have just achieved an operation that would have been more complex and more verbose had we used traditional methods.


We have defined a function spreadOut that returns the variable sentence, modify the function using the spread operator so that it returns the array ['learning', 'to', 'code', 'is', 'fun'].

Monday, December 17, 2018

Basic Data Structures: Access an Array's Contents Using Bracket Notation

Basic Data Structures: Access an Array's Contents Using Bracket Notation
The fundamental feature of any data structure is, of course, the ability to not only store data, but to be able to retrieve that data on command. So, now that we've learned how to create an array, let's begin to think about how we can access that array's information.

When we define a simple array as seen below, there are 3 items in it:

let ourArray = ["a", "b", "c"];
In an array, each array item has an index. This index doubles as the position of that item in the array, and how you reference it. However, it is important to note, that JavaScript arrays are zero-indexed, meaning that the first element of an array is actually at the zeroth position, not the first.

In order to retrieve an element from an array we can enclose an index in brackets and append it to the end of an array, or more commonly, to a variable which references an array object. This is known as bracket notation.

For example, if we want to retrieve the "a" from ourArray and assign it to a variable, we can do so with the following code:

let ourVariable = ourArray[0];
// ourVariable equals "a"
In addition to accessing the value associated with an index, you can also set an index to a value using the same notation:

ourArray[1] = "not b anymore";
// ourArray now equals ["a", "not b anymore", "c"];
Using bracket notation, we have now reset the item at index 1 from "b", to "not b anymore".


In order to complete this challenge, set the 2nd position (index 1) of myArray to anything you want, besides "b".